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x^2+14x-614x+19=0
We add all the numbers together, and all the variables
x^2-600x+19=0
a = 1; b = -600; c = +19;
Δ = b2-4ac
Δ = -6002-4·1·19
Δ = 359924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{359924}=\sqrt{4*89981}=\sqrt{4}*\sqrt{89981}=2\sqrt{89981}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-2\sqrt{89981}}{2*1}=\frac{600-2\sqrt{89981}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+2\sqrt{89981}}{2*1}=\frac{600+2\sqrt{89981}}{2} $
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